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72 lines
2.4 KiB
TeX
72 lines
2.4 KiB
TeX
\section{Payment Orchestration}
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\subsection{Multi-Processor Architecture}
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Hanzo Checkout integrates with multiple payment processors to optimize for cost, success rate, and availability:
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\begin{equation}
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\mathcal{G} = \{g_1, g_2, \ldots, g_n\}
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\end{equation}
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where each gateway $g_i$ has characteristics:
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\begin{itemize}
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\item $fee_i(a)$: transaction fee function
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\item $success_i$: historical success rate
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\item $latency_i$: average response time
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\item $cards_i \subseteq \mathcal{CARD\_TYPES}$: supported card types
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\end{itemize}
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\subsection{Routing Algorithm}
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\begin{definition}[Routing Score]
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For transaction $T$ and gateway $g$, the routing score is:
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\begin{equation}
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score(T, g) = w_s \cdot success_g - w_f \cdot fee_g(T.a) - w_l \cdot latency_g
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\end{equation}
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where $w_s, w_f, w_l$ are merchant-configurable weights.
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\end{definition}
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\begin{algorithm}
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\caption{Intelligent Payment Routing}
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\begin{algorithmic}[1]
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\Function{RoutePayment}{$T$, $\mathcal{G}$}
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\State $eligible \gets \{g \in \mathcal{G} : supports(g, T)\}$
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\If{$eligible = \emptyset$}
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\State \Return \textsc{NoEligibleGateway}
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\EndIf
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\State $scores \gets \{(g, score(T, g)) : g \in eligible\}$
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\State $primary \gets \arg\max_{(g,s) \in scores} s$
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\State $result \gets$ \Call{ProcessPayment}{$T$, $primary$}
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\If{$result.success$}
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\State \Return $result$
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\EndIf
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\State \Comment{Automatic failover}
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\For{$g \in eligible \setminus \{primary\}$ \textbf{by} $score$}
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\State $result \gets$ \Call{ProcessPayment}{$T$, $g$}
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\If{$result.success$}
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\State \Return $result$
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\EndIf
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\EndFor
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\State \Return \textsc{AllGatewaysFailed}
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\EndFunction
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\end{algorithmic}
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\end{algorithm}
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\subsection{Dynamic Fee Optimization}
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Transaction fees vary by card type, transaction amount, and geographic region. We model the fee structure as:
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\begin{equation}
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fee(T, g) = base_g + rate_g \cdot T.a + surcharge(T.card\_type, g)
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\end{equation}
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\begin{theorem}[Cost Minimization]
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For a set of transactions $\mathcal{T}$ over time period $t$, our routing algorithm achieves cost within $(1 + \epsilon)$ of optimal:
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\begin{equation}
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\sum_{T \in \mathcal{T}} fee(T, route(T)) \leq (1 + \epsilon) \sum_{T \in \mathcal{T}} \min_{g \in \mathcal{G}} fee(T, g)
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\end{equation}
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where $\epsilon \rightarrow 0$ as $|\mathcal{T}| \rightarrow \infty$.
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\end{theorem}
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