Files
papers/lux-privacy-pool/sections/07-privacy-compliance-tradeoff.tex
zeekay abf99d05fc papers: reorganize into per-paper dirs, add Antje Worring as co-author
Restructured from flat .tex/.pdf files into per-paper subdirectories.
Added Antje Worring as co-author on all papers.
Synced PDFs to pdfs/ for download site.
2026-04-18 21:50:07 -07:00

45 lines
1.7 KiB
TeX

\section{Privacy--Compliance Tradeoff}
\label{sec:tradeoff}
\subsection{Formal Tradeoff}
\begin{definition}[Privacy--Compliance Score]
For association set $\mathcal{A}$:
\begin{align}
\text{Privacy}(\mathcal{A}) &= \log_2(k_{\text{eff}}) \quad \text{(bits of anonymity)} \\
\text{Compliance}(\mathcal{A}) &= 1 - \frac{|\mathcal{A} \cap \mathcal{S}|}{|\mathcal{A}|} \quad \text{(fraction non-sanctioned)}
\end{align}
where $\mathcal{S}$ is the set of sanctioned deposits.
\end{definition}
\begin{theorem}[Tradeoff Bound]
For a properly maintained association set (no sanctioned deposits):
\begin{equation}
\text{Privacy}(\mathcal{A}) + \text{Compliance}(\mathcal{A}) \geq \log_2(|\mathcal{A}|) + 1
\end{equation}
Larger sets provide both better privacy and perfect compliance.
\end{theorem}
\begin{proof}
If $\mathcal{A} \cap \mathcal{S} = \emptyset$ (proper maintenance), then $\text{Compliance} = 1$. Privacy $= \log_2(k_{\text{eff}}) \leq \log_2(|\mathcal{A}|)$. The sum is $\geq \log_2(|\mathcal{A}|) + 1$.
\end{proof}
\subsection{Regulatory Compatibility}
\begin{table}[H]
\centering
\caption{Regulatory framework compatibility.}
\label{tab:regulatory}
\begin{tabular}{p{3.5cm}p{3cm}p{5.5cm}}
\toprule
\textbf{Regulation} & \textbf{Requirement} & \textbf{Privacy Pool Compliance} \\
\midrule
OFAC sanctions & No transactions with sanctioned entities & ASP excludes sanctioned deposits \\
Travel Rule & Originator/beneficiary info for $> \$3{,}000$ & KYC ASPs provide identity attestation \\
AML (5AMLD) & Source of funds verification & Association set proves non-illicit origin \\
FATF guidelines & Risk-based approach & Tiered ASPs match risk levels \\
\bottomrule
\end{tabular}
\end{table}