mirror of
https://github.com/zap-proto/d.git
synced 2026-10-30 15:05:27 +00:00
Rename the capnproto-dlang fork to zap-dlang: source/capnproto/ -> source/zap/ (module/import paths capnproto.* -> zap.*), compiler plugin capnpc-dlang -> zapc-dlang, schemas .capnp -> .zap, Makefile pkg-config/-lcapnp -> zap/-lzap, README/CONTRIBUTORS rebranded with canonical zap-proto.io/zap-proto.dev/ github.com/zap-proto/d links. Pure mechanical rename: no logic changes. Upstream Sandstorm MIT headers preserved.
192 lines
5.1 KiB
D
192 lines
5.1 KiB
D
// Copyright (c) 2013-2014 Sandstorm Development Group, Inc. and contributors
|
|
// Licensed under the MIT License:
|
|
//
|
|
// Permission is hereby granted, free of charge, to any person obtaining a copy
|
|
// of this software and associated documentation files (the "Software"), to deal
|
|
// in the Software without restriction, including without limitation the rights
|
|
// to use, copy, modify, merge, publish, distribute, sublicense, and/or sell
|
|
// copies of the Software, and to permit persons to whom the Software is
|
|
// furnished to do so, subject to the following conditions:
|
|
//
|
|
// The above copyright notice and this permission notice shall be included in
|
|
// all copies or substantial portions of the Software.
|
|
//
|
|
// THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
|
|
// IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
|
|
// FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
|
|
// AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
|
|
// LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,
|
|
// OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN
|
|
// THE SOFTWARE.
|
|
|
|
module zap.PackedOutputStream;
|
|
|
|
import java.io.IOException;
|
|
import java.nio.channels.WritableByteChannel;
|
|
import java.nio.ByteBuffer;
|
|
|
|
import zap.BufferedOutputStream;
|
|
|
|
final class PackedOutputStream : WritableByteChannel
|
|
{
|
|
public: //Methods.
|
|
this(BufferedOutputStream output)
|
|
{
|
|
this.inner = output;
|
|
}
|
|
|
|
size_t write(ref ByteBuffer inBuf)
|
|
{
|
|
auto length = inBuf.remaining();
|
|
auto out_ = this.inner.getWriteBuffer();
|
|
|
|
auto slowBuffer = ByteBuffer(new ubyte[](20));
|
|
|
|
auto inPtr = inBuf.position;
|
|
auto inEnd = inPtr + length;
|
|
while(inPtr < inEnd)
|
|
{
|
|
if(out_.remaining() < 10)
|
|
{
|
|
//# Oops, we're out of space. We need at least 10
|
|
//# bytes for the fast path, since we don't
|
|
//# bounds-check on every byte.
|
|
|
|
if(out_ is &slowBuffer)
|
|
{
|
|
auto oldLimit = out_.limit;
|
|
out_.limit = out_.position;
|
|
out_.rewind();
|
|
this.inner.write(*out_);
|
|
out_.limit = oldLimit;
|
|
}
|
|
out_ = &slowBuffer;
|
|
out_.rewind();
|
|
}
|
|
|
|
auto tagPos = out_.position;
|
|
out_.position = tagPos + 1;
|
|
|
|
import std.meta;
|
|
ubyte bit0, bit1, bit2, bit3, bit4, bit5, bit6, bit7;
|
|
foreach(ref b; AliasSeq!(bit0, bit1, bit2, bit3, bit4, bit5, bit6, bit7))
|
|
{
|
|
ubyte curByte = inBuf.get!ubyte(inPtr);
|
|
b = (curByte != 0)? cast(ubyte)1 : cast(ubyte)0;
|
|
out_.put!ubyte(curByte);
|
|
out_.position += b - 1;
|
|
inPtr += 1;
|
|
}
|
|
|
|
ubyte tag = cast(ubyte)((bit0 << 0) | (bit1 << 1) | (bit2 << 2) | (bit3 << 3) |
|
|
(bit4 << 4) | (bit5 << 5) | (bit6 << 6) | (bit7 << 7));
|
|
|
|
out_.put!ubyte(tagPos, tag);
|
|
|
|
if(tag == 0)
|
|
{
|
|
//# An all-zero word is followed by a count of
|
|
//# consecutive zero words (not including the first
|
|
//# one).
|
|
auto runStart = inPtr;
|
|
auto limit = inEnd;
|
|
if(limit - inPtr > 255 * 8)
|
|
limit = inPtr + 255 * 8;
|
|
while(inPtr < limit && inBuf.get!long(inPtr) == 0)
|
|
inPtr += 8;
|
|
out_.put!ubyte(cast(byte)((inPtr - runStart)/8));
|
|
}
|
|
else if(tag == 0xff)
|
|
{
|
|
//# An all-nonzero word is followed by a count of
|
|
//# consecutive uncompressed words, followed by the
|
|
//# uncompressed words themselves.
|
|
|
|
//# Count the number of consecutive words in the input
|
|
//# which have no more than a single zero-byte. We look
|
|
//# for at least two zeros because that's the point
|
|
//# where our compression scheme becomes a net win.
|
|
|
|
auto runStart = inPtr;
|
|
auto limit = inEnd;
|
|
if(limit - inPtr > 255 * 8)
|
|
limit = inPtr + 255 * 8;
|
|
|
|
while(inPtr < limit)
|
|
{
|
|
byte c = 0;
|
|
foreach(ii; 0..8)
|
|
{
|
|
c += (inBuf.get!byte(inPtr) == 0? 1 : 0);
|
|
inPtr += 1;
|
|
}
|
|
if(c >= 2)
|
|
{
|
|
//# Un-read the word with multiple zeros, since
|
|
//# we'll want to compress that one.
|
|
inPtr -= 8;
|
|
break;
|
|
}
|
|
}
|
|
|
|
auto count = inPtr - runStart;
|
|
out_.put!ubyte(cast(byte)(count / 8));
|
|
|
|
if(count <= out_.remaining())
|
|
{
|
|
//# There's enough space to memcpy.
|
|
inBuf.position = runStart;
|
|
ByteBuffer slice = inBuf.slice();
|
|
slice.limit = count;
|
|
out_.put!ByteBuffer(slice);
|
|
}
|
|
else
|
|
{
|
|
//# Input overruns the output buffer. We'll give it
|
|
//# to the output stream in one chunk and let it
|
|
//# decide what to do.
|
|
|
|
if(out_ is &slowBuffer)
|
|
{
|
|
auto oldLimit = out_.limit;
|
|
out_.limit = out_.position;
|
|
out_.rewind();
|
|
this.inner.write(*out_);
|
|
out_.limit = oldLimit;
|
|
}
|
|
|
|
inBuf.position = runStart;
|
|
ByteBuffer slice = inBuf.slice();
|
|
slice.limit = count;
|
|
while(!slice.empty())
|
|
this.inner.write(slice);
|
|
out_ = this.inner.getWriteBuffer();
|
|
}
|
|
}
|
|
}
|
|
|
|
if(out_ is &slowBuffer)
|
|
{
|
|
out_.limit = out_.position;
|
|
out_.rewind();
|
|
this.inner.write(*out_);
|
|
}
|
|
|
|
inBuf.position = inPtr;
|
|
return length;
|
|
}
|
|
|
|
void close()
|
|
{
|
|
this.inner.close();
|
|
}
|
|
|
|
bool isOpen()
|
|
{
|
|
return this.inner.isOpen();
|
|
}
|
|
|
|
package: //Variables.
|
|
BufferedOutputStream inner;
|
|
}
|